2cos^2x+2sin^2x=2

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Solution for 2cos^2x+2sin^2x=2 equation: 


Simplifying
2cos2x + 2sin2x = 2

Solving
2cos2x + 2in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
2cos2x + 2in2sx + -2in2sx = 2 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
2cos2x + 0 = 2 + -2in2sx
2cos2x = 2 + -2in2sx

Divide each side by '2os2x'.
c = o-1s-2x-1 + -1in2o-1s-1

Simplifying
c = o-1s-2x-1 + -1in2o-1s-1

Reorder the terms:
c = -1in2o-1s-1 + o-1s-2x-1

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